What is (\partial)/(\partial x)(sin(-x)cos(2y)) ?

The answer to (\partial)/(\partial x)(sin(-x)cos(2y)) is -cos(2y)cos(x)

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(\partial)/(\partial x)(sin(-x)cos(2y))

\frac{\partial}{\partial x} (sin (- x) cos (2 y))

- cos (2 y) cos (x)

Solution steps

\frac{\partial}{\partial x} (sin (- x) cos (2 y))

Simplify

sin (- x) cos (2 y) : - sin (x) cos (2 y)

= \frac{\partial}{\partial x} (- sin (x) cos (2 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - cos (2 y) \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= - cos (2 y) cos (x)

x \to 0 lim (\frac{ln ( 3 x + 1 )}{x})

19 - x^{2}

\frac{\partial}{\partial x} (ln (x^{2} + y^{2}))

y^{^{''}} = 4 y

\int tan (2 x) (sec (2 x))^{2} d x

What is (\partial)/(\partial x)(sin(-x)cos(2y)) ?
The answer to (\partial)/(\partial x)(sin(-x)cos(2y)) is -cos(2y)cos(x)