What is the derivative of 4ln(2x) ?

The derivative of 4ln(2x) is 4/x

What is the first derivative of 4ln(2x) ?

The first derivative of 4ln(2x) is 4/x

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\frac{d}{d x} (4 ln (2 x))

\frac{4}{x}

Solution steps

\frac{d}{d x} (4 ln (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (ln (2 x))

Apply the chain rule:

\frac{1}{2 x} \frac{d}{d x} (2 x)

= \frac{1}{2 x} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 4 \cdot \frac{1}{2 x} \cdot 2

Simplify

4 \cdot \frac{1}{2 x} \cdot 2 : \frac{4}{x}

= \frac{4}{x}

x \to 0 lim ((1 + 5 x)^{\frac{3}{x}})

\frac{( x ^{4} + 2 )}{ln ( x )}

\frac{\partial}{\partial x} (e^{- x y})

n = 0 \sum \infty n^{2} x^{n}

What is the derivative of 4ln(2x) ?
The derivative of 4ln(2x) is 4/x
What is the first derivative of 4ln(2x) ?
The first derivative of 4ln(2x) is 4/x