What is the integral of x^2cos(x^3+1) ?

The integral of x^2cos(x^3+1) is 1/3 sin(x^3+1)+C

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integral of x^2cos(x^3+1)

\int x^{2} cos (x^{3} + 1) d x

\frac{1}{3} sin (x^{3} + 1) + C

Solution steps

\int x^{2} cos (x^{3} + 1) d x

Apply u-substitution

: \int \frac{cos ( u )}{3} d u

= \int \frac{cos ( u )}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{3} sin (u)

Substitute back

u = x^{3} + 1

= \frac{1}{3} sin (x^{3} + 1)

Add a constant to the solution

= \frac{1}{3} sin (x^{3} + 1) + C

\int (- \frac{4000}{x ^{2}}) d x

\frac{d}{d x} (3 e^{3 x} cos (2 x) - 2 e^{3 x} sin (2 x))

x^{2} d x + y (x - 1) d y = 0

4 + x^{6}

x e^{x^{2}}

What is the integral of x^2cos(x^3+1) ?
The integral of x^2cos(x^3+1) is 1/3 sin(x^3+1)+C