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Popular >

y^'= x/y ,y(0)=-1

Solution

y^{^{'}} = \frac{x}{y}, y (0) = - 1

Solution

y = - x^{2} + 1

Solution steps

y^{'} (x) = \frac{x}{y}

Solve separable ODE:

y = - x^{2} + 1

y = - x^{2} + 1

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\int 9 x ln (3 x) d x

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\frac{10 e ^{- s}}{5 s + 1}

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\frac{d}{d x} (a (x - sin (x)))

derivative of f(x)=arctan(x/2)derivative of

f (x) = arctan (\frac{x}{2})

Frequently Asked Questions (FAQ)

What is the solution for y^'= x/y ,y(0)=-1 ?
The solution for y^'= x/y ,y(0)=-1 is y=-sqrt(x^2+1)