What is area y=sqrt(3x)+1,y=x+1 ?

The answer to area y=sqrt(3x)+1,y=x+1 is 3/2

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area y=sqrt(3x)+1,y=x+1

area

y = 3 x + 1, y = x + 1

\frac{3}{2}

Decimal Notation

1.5

Solution steps

Apply the area formula:

\int_{0}^{3} 3 x + 1 - (x + 1) d x

Solve

\int_{0}^{3} 3 x + 1 - (x + 1) d x : \frac{3}{2}

The area is:

= \frac{3}{2}

\int 5 u^{5} u^{6} + 5 d u

\frac{d}{d x} (\frac{π}{( 2 x ) ^{4}})

\frac{d y}{d x} = 2 x y - 6 x

\frac{1}{( 1 - x ) ^{4}}

f (x) = (7 x + 1)^{2}