What is the derivative of 3x+1/x ?

The derivative of 3x+1/x is 3-1/(x^2)

What is the first derivative of 3x+1/x ?

The first derivative of 3x+1/x is 3-1/(x^2)

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\frac{d}{d x} (3 x + \frac{1}{x})

3 - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 3 - \frac{1}{x ^{2}}

\int_{- 8}^{2} 16 - 6 x - x d x

\int \frac{2}{x ^{2} + 1} d x

x^{2} y^{^{'}} = x y + 3 y^{2}

\int 2 sin (t) cos (t) d t

\frac{d s}{d s}

What is the derivative of 3x+1/x ?
The derivative of 3x+1/x is 3-1/(x^2)
What is the first derivative of 3x+1/x ?
The first derivative of 3x+1/x is 3-1/(x^2)