What is the derivative of x^3+x^2-8x+7 ?

The derivative of x^3+x^2-8x+7 is 3x^2+2x-8

What is the first derivative of x^3+x^2-8x+7 ?

The first derivative of x^3+x^2-8x+7 is 3x^2+2x-8

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\frac{d}{d x} (x^{3} + x^{2} - 8 x + 7)

3 x^{2} + 2 x - 8

Solution steps

\frac{d}{d x} (x^{3} + x^{2} - 8 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (7) = 0

= 3 x^{2} + 2 x - 8 + 0

Simplify

= 3 x^{2} + 2 x - 8

\int 2^{u} d u

\frac{d y}{d x} = \frac{( y ^{2} - 1 )}{x ^{2} - 1}, y (2) = 2

y^{^{''}} - y^{^{'}} + 289 y = 17 sin (17 t)

\int 14 x - 5 d x

x = y^{4}, x = y^{5}

What is the derivative of x^3+x^2-8x+7 ?
The derivative of x^3+x^2-8x+7 is 3x^2+2x-8
What is the first derivative of x^3+x^2-8x+7 ?
The first derivative of x^3+x^2-8x+7 is 3x^2+2x-8