What is the integral of e^{2x+6} ?

The integral of e^{2x+6} is 1/2 e^{2x+6}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{2x+6}

\int e^{2 x + 6} d x

\frac{1}{2} e^{2 x + 6} + C

Solution steps

\int e^{2 x + 6} d x

Apply u-substitution

: \int e^{u} \frac{1}{2} d u

= \int e^{u} \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{2} e^{u}

Substitute back

u = 2 x + 6

= \frac{1}{2} e^{2 x + 6}

Add a constant to the solution

= \frac{1}{2} e^{2 x + 6} + C

\int ln (x^{8}) d x

\frac{d}{d x} (6^{6 - x^{2}})

y = - 2 x + 7

\int_{7}^{14} - 30 x^{2} + 420 x d x

\int \frac{1}{x ^{5} 9 x ^{2} - 1} d x