What is the derivative of f(x)=x^3-3/2 x^2 ?

The derivative of f(x)=x^3-3/2 x^2 is 3x^2-3x

What is the first derivative of f(x)=x^3-3/2 x^2 ?

The first derivative of f(x)=x^3-3/2 x^2 is 3x^2-3x

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derivative of

f (x) = x^{3} - \frac{3}{2} x^{2}

3 x^{2} - 3 x

Solution steps

\frac{d}{d x} (x^{3} - \frac{3}{2} x^{2})

Simplify

x^{3} - \frac{3}{2} x^{2} : x^{3} - \frac{3 x ^{2}}{2}

= \frac{d}{d x} (x^{3} - \frac{3 x ^{2}}{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (\frac{3 x ^{2}}{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (\frac{3 x ^{2}}{2}) = 3 x

= 3 x^{2} - 3 x

y = 2 - ∣ x ∣, y = x^{2}

\frac{1}{x} + 6

\frac{1}{s ^{2} - π}

\int \frac{15}{x ^{2} - 1} d x

\int 2 x (x^{2} + 8)^{6} d x

What is the derivative of f(x)=x^3-3/2 x^2 ?
The derivative of f(x)=x^3-3/2 x^2 is 3x^2-3x
What is the first derivative of f(x)=x^3-3/2 x^2 ?
The first derivative of f(x)=x^3-3/2 x^2 is 3x^2-3x