What is the derivative of 4cos(x^2)-8x^2sin(x^2) ?

The derivative of 4cos(x^2)-8x^2sin(x^2) is -24xsin(x^2)-16x^3cos(x^2)

What is the first derivative of 4cos(x^2)-8x^2sin(x^2) ?

The first derivative of 4cos(x^2)-8x^2sin(x^2) is -24xsin(x^2)-16x^3cos(x^2)

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derivative of

4 cos (x^{2}) - 8 x^{2} sin (x^{2})

- 24 x sin (x^{2}) - 16 x^{3} cos (x^{2})

Solution steps

\frac{d}{d x} (4 cos (x^{2}) - 8 x^{2} sin (x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 cos (x^{2})) - \frac{d}{d x} (8 x^{2} sin (x^{2}))

\frac{d}{d x} (4 cos (x^{2})) = - 8 x sin (x^{2})

\frac{d}{d x} (8 x^{2} sin (x^{2})) = 8 (2 x sin (x^{2}) + 2 x^{3} cos (x^{2}))

= - 8 x sin (x^{2}) - 8 (2 x sin (x^{2}) + 2 x^{3} cos (x^{2}))

Simplify

- 8 x sin (x^{2}) - 8 (2 x sin (x^{2}) + 2 x^{3} cos (x^{2})) : - 24 x sin (x^{2}) - 16 x^{3} cos (x^{2})

= - 24 x sin (x^{2}) - 16 x^{3} cos (x^{2})

\int_{0}^{4} 1 + \frac{9}{4} x d x

\int_{0}^{6} 3 4 x + 1 d x

\int \frac{1}{x 6 x + 4} d x

y^{^{''}} = e^{3 t}

\int_{0}^{4} x^{3} e^{x} d x

What is the derivative of 4cos(x^2)-8x^2sin(x^2) ?
The derivative of 4cos(x^2)-8x^2sin(x^2) is -24xsin(x^2)-16x^3cos(x^2)
What is the first derivative of 4cos(x^2)-8x^2sin(x^2) ?
The first derivative of 4cos(x^2)-8x^2sin(x^2) is -24xsin(x^2)-16x^3cos(x^2)