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Popular >

derivative of (7e^x+4e^{-x}/8)

Solution

\frac{d}{d x} (\frac{7 e ^{x} + 4 e ^{- x}}{8})

Solution

\frac{1}{8} (7 e^{x} - 4 e^{- x})

Solution steps

\frac{d}{d x} (\frac{7 e ^{x} + 4 e ^{- x}}{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (7 e^{x} + 4 e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{8} (\frac{d}{d x} (7 e^{x}) + \frac{d}{d x} (4 e^{- x}))

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

\frac{d}{d x} (4 e^{- x}) = - 4 e^{- x}

= \frac{1}{8} (7 e^{x} - 4 e^{- x})

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\int - 2 e^{- t} d t

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\int \frac{( x ^{2} )}{( 1 + x ^{3} ) ^{2}} d x

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x^{2} - 1, x + 1

integral from 2 to 6 of (x^3+x)

\int_{2}^{6} (x^{3} + x) d x

Frequently Asked Questions (FAQ)

What is the derivative of (7e^x+4e^{-x}/8) ?
The derivative of (7e^x+4e^{-x}/8) is 1/8 (7e^x-4e^{-x})
What is the first derivative of (7e^x+4e^{-x}/8) ?
The first derivative of (7e^x+4e^{-x}/8) is 1/8 (7e^x-4e^{-x})