What is the derivative of y=x^2+2x+1 ?

The derivative of y=x^2+2x+1 is 2x+2

What is the first derivative of y=x^2+2x+1 ?

The first derivative of y=x^2+2x+1 is 2x+2

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derivative of

y = x^{2} + 2 x + 1

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 x + 2 + 0

Simplify

= 2 x + 2

x \frac{d y}{d x} = y^{2} + 1

\int (\frac{1}{4 + x ^{2}}) d x

(\frac{x ^{2}}{x ^{2} - x - 2})^{^{'}}

\frac{2 s - 3}{( s + 4 ) ( s - 3 ) ^{3}}

\int \frac{15 x ^{4}}{x ^{5} + 7} d x

What is the derivative of y=x^2+2x+1 ?
The derivative of y=x^2+2x+1 is 2x+2
What is the first derivative of y=x^2+2x+1 ?
The first derivative of y=x^2+2x+1 is 2x+2