What is the sum from n=1 to infinity of 1/(n^{4/3)} ?

The sum from n=1 to infinity of 1/(n^{4/3)} is converges

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sum from n=1 to infinity of 1/(n^{4/3)}

n = 1 \sum \infty \frac{1}{n ^{\frac{4}{3}}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{\frac{4}{3}}}

Apply p-Series Test:

converges

= converges

\frac{\partial}{\partial x} (3 x + 6 y)

x \to 0 - lim (\frac{3}{x ^{2}})

y = x^{2}, y = x + 2, y = 0

\int \frac{x + 3}{x ^{2} + 9} d x

6 t - 4 t^{3} + 9

What is the sum from n=1 to infinity of 1/(n^{4/3)} ?
The sum from n=1 to infinity of 1/(n^{4/3)} is converges