What is the solution for (dy)/(dx)=(x^2y-y)/(y+1) ?

The solution for (dy)/(dx)=(x^2y-y)/(y+1) is y=\W(1/(e^{(-x^3+3x-c_{1))/3}})

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(dy)/(dx)=(x^2y-y)/(y+1)

\frac{d y}{d x} = \frac{x ^{2} y - y}{y + 1}

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

Solution steps

\frac{d y}{d x} = \frac{x ^{2} y - y}{y + 1}

Solve separable ODE:

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

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What is the solution for (dy)/(dx)=(x^2y-y)/(y+1) ?
The solution for (dy)/(dx)=(x^2y-y)/(y+1) is y=\W(1/(e^{(-x^3+3x-c_{1))/3}})