What is (\partial)/(\partial y)(-xy^2+xy) ?

The answer to (\partial)/(\partial y)(-xy^2+xy) is -2xy+x

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(\partial)/(\partial y)(-xy^2+xy)

\frac{\partial}{\partial y} (- x y^{2} + x y)

- 2 x y + x

Solution steps

\frac{\partial}{\partial y} (- x y^{2} + x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial y} (x y^{2}) + \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (x y^{2}) = 2 x y

\frac{\partial}{\partial y} (x y) = x

= - 2 x y + x

\frac{\partial}{\partial x} (x^{3} ln (y^{2}))

x \to 3 + lim (4 x - a + b)

∣ x ∣, 5 - ∣ x ∣

\frac{( 72 )}{( 4800 + 88 s )}

n = 4 \sum \infty \frac{1}{2 ^{n}}

What is (\partial)/(\partial y)(-xy^2+xy) ?
The answer to (\partial)/(\partial y)(-xy^2+xy) is -2xy+x