What is area y=x^2,y=sqrt(x),y=0 ?

The answer to area y=x^2,y=sqrt(x),y=0 is 1/3

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area y=x^2,y=sqrt(x),y=0

area

y = x^{2}, y = x, y = 0

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x^{2} = x : x = 0, x = 1

x^{2} = 0 : x = 0

x = 0 : x = 0

= \int_{0}^{1} ∣ f_{1} (x) - f_{2} (x) ∣ d x

= \int_{0}^{1} x^{2} - x d x

\int_{0}^{1} x^{2} - x d x = \frac{1}{3}

= \frac{1}{3}

n = 2 \sum \infty e^{3 - 4 n}

f (x) = (2 x - 8) 4 (x^{2} + x + 1) 5

\frac{s + 2}{s ^{2} - s - 12}

x \to 0 lim (3 x^{7 x})

\int \frac{x ^{2} + 24 x - 16}{x ^{3} - 16 x} d x

What is area y=x^2,y=sqrt(x),y=0 ?
The answer to area y=x^2,y=sqrt(x),y=0 is 1/3