What is the derivative of f(x)=(x^2-8)(x^2+9) ?

The derivative of f(x)=(x^2-8)(x^2+9) is 4x^3+2x

What is the first derivative of f(x)=(x^2-8)(x^2+9) ?

The first derivative of f(x)=(x^2-8)(x^2+9) is 4x^3+2x

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derivative of

f (x) = (x^{2} - 8) (x^{2} + 9)

4 x^{3} + 2 x

Solution steps

\frac{d}{d x} ((x^{2} - 8) (x^{2} + 9))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2} - 8, g = x^{2} + 9

= \frac{d}{d x} (x^{2} - 8) (x^{2} + 9) + \frac{d}{d x} (x^{2} + 9) (x^{2} - 8)

\frac{d}{d x} (x^{2} - 8) = 2 x

\frac{d}{d x} (x^{2} + 9) = 2 x

= 2 x (x^{2} + 9) + 2 x (x^{2} - 8)

Simplify

2 x (x^{2} + 9) + 2 x (x^{2} - 8) : 4 x^{3} + 2 x

= 4 x^{3} + 2 x

\int x - 3 d x

\int \frac{( sin ( x ) )}{x} d x

\int - 0.2 x^{2} + 12 x d x

\int 4 x^{4} + x^{2} d x

f (x) = \frac{4}{( 3 x ) ^{- 2}}

What is the derivative of f(x)=(x^2-8)(x^2+9) ?
The derivative of f(x)=(x^2-8)(x^2+9) is 4x^3+2x
What is the first derivative of f(x)=(x^2-8)(x^2+9) ?
The first derivative of f(x)=(x^2-8)(x^2+9) is 4x^3+2x