What is area y=10x^4-10x^2,y=7x^2 ?

The answer to area y=10x^4-10x^2,y=7x^2 is (289sqrt(34))/(75sqrt(5))

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area y=10x^4-10x^2,y=7x^2

area

y = 10 x^{4} - 10 x^{2}, y = 7 x^{2}

\frac{289 34}{75 5}

Decimal Notation

10.04826 \dots

Solution steps

Apply the area formula:

\int_{- \frac{17}{10}}^{\frac{17}{10}} 10 x^{4} - 17 x^{2} d x

Solve

\int_{- \frac{17}{10}}^{\frac{17}{10}} 10 x^{4} - 17 x^{2} d x : \frac{289 34}{75 5}

The area is:

= \frac{289 34}{75 5}

x + y \cdot \frac{d y}{d x} = 0

(0.3) (4.1)

y = e^{x}, y = e^{- 4 x}, x = ln (4)

\int \frac{1}{x ( x + 1 ) ( x + 2 )} d x

\frac{d}{d x} (e^{\frac{- x}{4}})

What is area y=10x^4-10x^2,y=7x^2 ?
The answer to area y=10x^4-10x^2,y=7x^2 is (289sqrt(34))/(75sqrt(5))