What is (\partial)/(\partial x)(x-x^2y) ?

The answer to (\partial)/(\partial x)(x-x^2y) is 1-2yx

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(\partial)/(\partial x)(x-x^2y)

\frac{\partial}{\partial x} (x - x^{2} y)

1 - 2 y x

Solution steps

\frac{\partial}{\partial x} (x - x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (x^{2} y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

= 1 - 2 y x

\frac{d}{d x} (\frac{sin ( 2 x )}{4})

\int_{0}^{π} cos^{4} (x) sin (x) d x

\frac{\partial}{\partial y} (x + 2 y - 6)

\int_{- 8}^{8} 64 - x^{2} d x

\int 9 x e^{x^{2}} d x

What is (\partial)/(\partial x)(x-x^2y) ?
The answer to (\partial)/(\partial x)(x-x^2y) is 1-2yx