What is the derivative of x^4y ?

The derivative of x^4y is 4x^3y+(dy)/(dx)x^4

What is the first derivative of x^4y ?

The first derivative of x^4y is 4x^3y+(dy)/(dx)x^4

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\frac{d}{d x} (x^{4} y)

4 x^{3} y + \frac{d y}{d x} x^{4}

Solution steps

\frac{d}{d x} (x^{4} y)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{4}, g = y

= \frac{d}{d x} (x^{4}) y + \frac{d y}{d x} x^{4}

\frac{d}{d x} (x^{4}) = 4 x^{3}

= 4 x^{3} y + \frac{d y}{d x} x^{4}

\frac{d}{d x} (\frac{1}{x ^{2} y})

\int_{0}^{1} x^{2} (x + 1)^{7} d x

\frac{\partial}{\partial y} (2 x y^{3} - 4)

y^{^{''}} - 18 y^{^{'}} + 81 y = 0

\int 16 tan^{3} (x) d x

What is the derivative of x^4y ?
The derivative of x^4y is 4x^3y+(dy)/(dx)x^4
What is the first derivative of x^4y ?
The first derivative of x^4y is 4x^3y+(dy)/(dx)x^4