What is the limit as x approaches 3 of (x-2)/(x^2-9) ?

The limit as x approaches 3 of (x-2)/(x^2-9) is diverges

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limit as x approaches 3 of (x-2)/(x^2-9)

x \to 3 lim (\frac{x - 2}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{x - 2}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x - 2}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{x - 2}{x ^{2} - 9}) = - \infty

= diverges

\int \frac{1}{x ^{2} + 4 x + 5} d x

f (x) = \frac{9}{x - 3}, at x = 2

y = e^{5}

\frac{d}{d x} (x^{\frac{3}{4}} - 3 x^{\frac{1}{4}})

(3.3 x + 5)^{0.37}

What is the limit as x approaches 3 of (x-2)/(x^2-9) ?
The limit as x approaches 3 of (x-2)/(x^2-9) is diverges