What is inverse oflaplace ((e^{-2s}))/s ?

The answer to inverse oflaplace ((e^{-2s}))/s is \H(t-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace ((e^{-2s}))/s

inverse laplace

\frac{( e ^{- 2 s} )}{s}

H (t - 2)

Solution steps

L^{- 1} {\frac{( e ^{- 2 s} )}{s}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

Where

H (t)

is Heaviside step function

= H (t - 2) L^{- 1} {\frac{1}{s}} (t - 2)

L^{- 1} {\frac{1}{s}} : H (t)

= H (t - 2) H (t - 2)

= H (t - 2)

\int - 2 x^{5} - 5 x^{3} + 3 x^{2} + 1 - 4 e^{x} d x

\int_{2}^{3} \frac{2}{t ^{2} - 1} d t

\int \frac{5}{x x ^{2} + 9} d x

x

What is inverse oflaplace ((e^{-2s}))/s ?
The answer to inverse oflaplace ((e^{-2s}))/s is \H(t-2)