What is (\partial)/(\partial y)(sin(xy)+xsin(y)) ?

The answer to (\partial)/(\partial y)(sin(xy)+xsin(y)) is cos(xy)x+xcos(y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(sin(xy)+xsin(y))

\frac{\partial}{\partial y} (sin (x y) + x sin (y))

cos (x y) x + x cos (y)

Solution steps

\frac{\partial}{\partial y} (sin (x y) + x sin (y))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (sin (x y)) + \frac{\partial}{\partial y} (x sin (y))

\frac{\partial}{\partial y} (sin (x y)) = cos (x y) x

\frac{\partial}{\partial y} (x sin (y)) = x cos (y)

= cos (x y) x + x cos (y)

f (x) = \frac{6}{x ^{4}}

\int e^{- \frac{3}{2} x} d x

6 x^{3} - 9 x^{2} + 5 x - 2

7 cos (π x), 8 x^{2} - 2, [- 0.5, 0.5]

x \to - 1 lim (\frac{3 x ^{2} - 9 x - 12}{3 x + 3})

What is (\partial)/(\partial y)(sin(xy)+xsin(y)) ?
The answer to (\partial)/(\partial y)(sin(xy)+xsin(y)) is cos(xy)x+xcos(y)