What is implicit (dy)/(dx),7xy+1=0 ?

The answer to implicit (dy)/(dx),7xy+1=0 is (dy)/(dx)=-y/x

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implicit (dy)/(dx),7xy+1=0

implicit derivative

\frac{d y}{d x}, 7 x y + 1 = 0

\frac{d y}{d x} = - \frac{y}{x}

Solution steps

7 x y + 1 = 0

Treat

y

y (x)

Differentiate both sides:

7 (x \frac{d y}{d x} + y) = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{y}{x}

\frac{d y}{d x} = - \frac{y}{x}

\frac{d}{d x} (9^{x} ln (x))

5 t^{2} - 6 cos (3 t) + 8 e^{- t}

x \to \infty lim (x + \frac{2}{x})

x \to 4 lim (5 x)

\frac{s - 1}{s + 3}

What is implicit (dy)/(dx),7xy+1=0 ?
The answer to implicit (dy)/(dx),7xy+1=0 is (dy)/(dx)=-y/x