What is the sum from n=0 to infinity of (2/e)^n ?

The sum from n=0 to infinity of (2/e)^n is e/(e-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (2/e)^n

n = 0 \sum \infty (\frac{2}{e})^{n}

\frac{e}{e - 2}

Solution steps

n = 0 \sum \infty (\frac{2}{e})^{n}

Apply Series Geometric Test:

\frac{e}{e - 2}

= \frac{e}{e - 2}

(x^{2} + 4)^{5}

\int (e^{2 x}) d x

x^{x}

\frac{d}{d x} (\frac{1}{10 x + 11})

\int_{- \infty}^{0} \frac{1}{x ^{2} + 1} d x

What is the sum from n=0 to infinity of (2/e)^n ?
The sum from n=0 to infinity of (2/e)^n is e/(e-2)