What is laplacetransform 1+2t ?

The answer to laplacetransform 1+2t is 1/s+2/(s^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 1+2t

laplace transform

1 + 2 t

\frac{1}{s} + \frac{2}{s ^{2}}

Solution steps

L {1 + 2 t}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {1} + 2 L {t}

L {1} : \frac{1}{s}

L {t} : \frac{1}{s ^{2}}

= \frac{1}{s} + 2 \cdot \frac{1}{s ^{2}}

Refine

\frac{1}{s} + 2 \frac{1}{s ^{2}} : \frac{1}{s} + \frac{2}{s ^{2}}

= \frac{1}{s} + \frac{2}{s ^{2}}

\frac{d ^{2}}{d x ^{2}} (\frac{1}{1 + x ^{2}})

\int (3 x - \frac{4}{3} x^{\frac{3}{2}}) d x

x \to 1 - lim (arcsin (\frac{1}{x}))

t^{3} - 15 t^{2} + 72 t

\frac{d}{d x} (e^{- a x} cos (b x))

What is laplacetransform 1+2t ?
The answer to laplacetransform 1+2t is 1/s+2/(s^2)