What is the solution for (10+x^2)y^'-2xy=0 ?

The solution for (10+x^2)y^'-2xy=0 is y=10e^{c_{1}}+e^{c_{1}}x^2

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(10+x^2)y^'-2xy=0

(10 + x^{2}) y^{^{'}} - 2 x y = 0

y = 10 e^{c_{1}} + e^{c_{1}} x^{2}

Solution steps

(10 + x^{2}) y^{'} (x) - 2 x y = 0

Solve separable ODE:

y = 10 e^{c_{1}} + e^{c_{1}} x^{2}

y = 10 e^{c_{1}} + e^{c_{1}} x^{2}

\int x^{2} - 3 x + 7 d x

\frac{2}{3} x^{6}

\int_{7}^{8} \frac{1}{( x - 7 ) ^{\frac{3}{2}}} d x

(x + 1) (\frac{d y}{d x}) = (x + 6)

x \to 0 lim (x^{- 8})

What is the solution for (10+x^2)y^'-2xy=0 ?
The solution for (10+x^2)y^'-2xy=0 is y=10e^{c_{1}}+e^{c_{1}}x^2