What is the solution for (dr)/(dθ)+rtan(θ)=5sec(θ) ?

The solution for (dr)/(dθ)+rtan(θ)=5sec(θ) is r(θ)=(5tan(θ))/(sec(θ))+(c_{1})/(sec(θ))

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(dr)/(dθ)+rtan(θ)=5sec(θ)

\frac{d r}{d θ} + r tan (θ) = 5 sec (θ)

r (θ) = \frac{5 tan ( θ )}{sec ( θ )} + \frac{c _{1}}{sec ( θ )}

Solution steps

\frac{d r}{d θ} + r tan (θ) = 5 sec (θ)

Solve linear ODE:

r (θ) = \frac{5 tan ( θ )}{sec ( θ )} + \frac{c _{1}}{sec ( θ )}

r (θ) = \frac{5 tan ( θ )}{sec ( θ )} + \frac{c _{1}}{sec ( θ )}

\int \frac{\frac{1}{2}}{4 - 3 x ^{2}} d x

\int arcsec (y) d y

\int sec^{2} (θ) tan^{6} (θ) d θ

e^{p} (p + p p)

\frac{\partial}{\partial x} (\frac{y}{1 + x ^{2} y ^{2}})

What is the solution for (dr)/(dθ)+rtan(θ)=5sec(θ) ?
The solution for (dr)/(dθ)+rtan(θ)=5sec(θ) is r(θ)=(5tan(θ))/(sec(θ))+(c_{1})/(sec(θ))