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Popular >

y^'-a*y+b=0

Solution

y^{^{'}} - a \cdot y + b = 0

Solution

y = \frac{e ^{t a + c_{1} a}}{a} + \frac{b}{a}

Solution steps

y^{'} (t) - a \cdot y + b = 0

Solve separable ODE:

y = \frac{e ^{t a + c_{1} a}}{a} + \frac{b}{a}

y = \frac{e ^{t a + c_{1} a}}{a} + \frac{b}{a}

Popular Examples

y^'=((e^{(x/3)}+y))/2

y^{^{'}} = \frac{( e ^{(\frac{x}{3})} + y )}{2}

derivative of-4sin(8x)

\frac{d}{d x} (- 4 sin (8 x))

limit as x approaches 0 of x/(1+x)

x \to 0 lim (\frac{x}{1 + x})

area x^2-6,3 area

x^{2} - 6, 3

derivative of f(x)=-2x^4+x^{-2}-3x^{3/4}derivative of

f (x) = - 2 x^{4} + x^{- 2} - 3 x^{\frac{3}{4}}

Frequently Asked Questions (FAQ)

What is the solution for y^'-a*y+b=0 ?
The solution for y^'-a*y+b=0 is y=(e^{ta+c_{1}a})/a+b/a