What is (d^2)/(dx^2)(1/((x-1)^2)) ?

The answer to (d^2)/(dx^2)(1/((x-1)^2)) is 6/((x-1)^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2)/(dx^2)(1/((x-1)^2))

\frac{d ^{2}}{d x ^{2}} (\frac{1}{( x - 1 ) ^{2}})

\frac{6}{( x - 1 ) ^{4}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{1}{( x - 1 ) ^{2}})

\frac{d}{d x} (\frac{1}{( x - 1 ) ^{2}}) = - \frac{2}{( x - 1 ) ^{3}}

= \frac{d}{d x} (- \frac{2}{( x - 1 ) ^{3}})

\frac{d}{d x} (- \frac{2}{( x - 1 ) ^{3}}) = \frac{6}{( x - 1 ) ^{4}}

= \frac{6}{( x - 1 ) ^{4}}

\int x^{2} e^{20 x} d x

n = 0 \sum \infty (x - 5)^{n}

f (x) = 2 π x

f (x) = x + 7, at x = 2

\frac{d}{d x} (\frac{7 x - 11}{x})

What is (d^2)/(dx^2)(1/((x-1)^2)) ?
The answer to (d^2)/(dx^2)(1/((x-1)^2)) is 6/((x-1)^4)