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Popular >

y^'=9xe^y,y(0)=0

Solution

y^{^{'}} = 9 x e^{y}, y (0) = 0

Solution

y = - ln (- \frac{9 x ^{2}}{2} + 1)

Solution steps

y^{'} (x) = 9 x e^{y}

Solve separable ODE:

y = - ln (- \frac{9 x ^{2}}{2} + 1)

y = - ln (- \frac{9 x ^{2}}{2} + 1)

Popular Examples

area 7-2x^2,x^2+4 area

7 - 2 x^{2}, x^{2} + 4

limit as t approaches 0 of sin(2t)

t \to 0 lim (sin (2 t))

integral of 1/(x^3sqrt(x^2-9))

\int \frac{1}{x ^{3} x ^{2} - 9} d x

derivative of xlog_{e}(x)

\frac{d}{d x} (x lo g_{e} (x))

(\partial)/(\partial x)(7xy^9+x^5y^7)

\frac{\partial}{\partial x} (7 x y^{9} + x^{5} y^{7})

Frequently Asked Questions (FAQ)

What is the solution for y^'=9xe^y,y(0)=0 ?
The solution for y^'=9xe^y,y(0)=0 is y=-ln(-(9x^2)/2+1)