What is the derivative of 2x+4/x ?

The derivative of 2x+4/x is 2-4/(x^2)

What is the first derivative of 2x+4/x ?

The first derivative of 2x+4/x is 2-4/(x^2)

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\frac{d}{d x} (2 x + \frac{4}{x})

2 - \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (2 x + \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 2 - \frac{4}{x ^{2}}

\int \frac{18}{1 - cos ( 2 x )} d x

\int \frac{5 x ^{4}}{( 10 + x ^{5} ) ^{4}} d x

\int \frac{sin ( x )}{sec ( x )} d x

\int_{0}^{2} \frac{1}{( x - 2 ) ^{2}} d x

\int - \frac{y}{( x + 2 ) ^{2}} d x

What is the derivative of 2x+4/x ?
The derivative of 2x+4/x is 2-4/(x^2)
What is the first derivative of 2x+4/x ?
The first derivative of 2x+4/x is 2-4/(x^2)