What is (\partial)/(\partial v)(asin(u)cos(v)) ?

The answer to (\partial)/(\partial v)(asin(u)cos(v)) is -asin(u)sin(v)

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(\partial)/(\partial v)(asin(u)cos(v))

\frac{\partial}{\partial v} (a sin (u) cos (v))

- a sin (u) sin (v)

Solution steps

\frac{\partial}{\partial v} (a sin (u) cos (v))

Treat

a, u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a sin (u) \frac{\partial}{\partial v} (cos (v))

Apply the common derivative:

\frac{\partial}{\partial v} (cos (v)) = - sin (v)

= a sin (u) (- sin (v))

Simplify

= - a sin (u) sin (v)

\frac{d}{d x} (∣ x - 1 ∣ + ∣ 2 x + 3 ∣)

y = 2 x^{2}, y = 8 x - 6 x^{2}

\int_{0}^{4 π} x^{2} sin (2 x) d x

\int 5 - cos (x) d x

What is (\partial)/(\partial v)(asin(u)cos(v)) ?
The answer to (\partial)/(\partial v)(asin(u)cos(v)) is -asin(u)sin(v)