What is (\partial)/(\partial x)(cos(x-y^2)) ?

The answer to (\partial)/(\partial x)(cos(x-y^2)) is -sin(x-y^2)

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(\partial)/(\partial x)(cos(x-y^2))

\frac{\partial}{\partial x} (cos (x - y^{2}))

- sin (x - y^{2})

Solution steps

\frac{\partial}{\partial x} (cos (x - y^{2}))

Treat

y

as a constant

Apply the chain rule:

- sin (x - y^{2}) \frac{\partial}{\partial x} (x - y^{2})

= - sin (x - y^{2}) \frac{\partial}{\partial x} (x - y^{2})

\frac{\partial}{\partial x} (x - y^{2}) = 1

= - sin (x - y^{2}) \cdot 1

Simplify

= - sin (x - y^{2})

n = 3 \sum \infty \frac{1}{e n}

\frac{d y}{d x} = 0.0013 y (2500 - y)

\frac{d y}{d t} = 100 - y

\int_{0}^{3} 9

\int x (15 x + 8) d x

What is (\partial)/(\partial x)(cos(x-y^2)) ?
The answer to (\partial)/(\partial x)(cos(x-y^2)) is -sin(x-y^2)