What is the derivative of x^2-4x+1 ?

The derivative of x^2-4x+1 is 2x-4

What is the first derivative of x^2-4x+1 ?

The first derivative of x^2-4x+1 is 2x-4

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\frac{d}{d x} (x^{2} - 4 x + 1)

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

\int tan (2) (x) d x

\int x 2 x^{2} + 7 d x

\frac{\partial}{\partial t} (2 s t)

f (t) = 5 t^{2} + 31 t + 100

- \frac{3 x}{y}

What is the derivative of x^2-4x+1 ?
The derivative of x^2-4x+1 is 2x-4
What is the first derivative of x^2-4x+1 ?
The first derivative of x^2-4x+1 is 2x-4