What is the derivative of cos(2^{3x^2+5x-6}) ?

The derivative of cos(2^{3x^2+5x-6}) is -sin(2^{3x^2+5x-6})ln(2)*2^{3x^2+5x-6}(6x+5)

What is the first derivative of cos(2^{3x^2+5x-6}) ?

The first derivative of cos(2^{3x^2+5x-6}) is -sin(2^{3x^2+5x-6})ln(2)*2^{3x^2+5x-6}(6x+5)

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\frac{d}{d x} (cos (2^{3 x^{2} + 5 x - 6}))

- sin (2^{3 x^{2} + 5 x - 6}) ln (2) \cdot 2^{3 x^{2} + 5 x - 6} (6 x + 5)

Solution steps

\frac{d}{d x} (cos (2^{3 x^{2} + 5 x - 6}))

Apply the chain rule:

- sin (2^{3 x^{2} + 5 x - 6}) \frac{d}{d x} (2^{3 x^{2} + 5 x - 6})

= - sin (2^{3 x^{2} + 5 x - 6}) \frac{d}{d x} (2^{3 x^{2} + 5 x - 6})

\frac{d}{d x} (2^{3 x^{2} + 5 x - 6}) = ln (2) \cdot 2^{3 x^{2} + 5 x - 6} (6 x + 5)

= - sin (2^{3 x^{2} + 5 x - 6}) ln (2) \cdot 2^{3 x^{2} + 5 x - 6} (6 x + 5)

(18 + x^{2}) y^{^{'}} - 2 x y = 0

y^{^{'}} = y (x y^{6} + 2)

y^{^{'}} = \frac{4 t ^{3} + 1}{2 y - 6}

\frac{\partial}{\partial y} (x^{2} y^{3} - \frac{1}{1 + 9 x ^{2}})

f (x) = \frac{6}{x - 1}, at x = 3

What is the derivative of cos(2^{3x^2+5x-6}) ?
The derivative of cos(2^{3x^2+5x-6}) is -sin(2^{3x^2+5x-6})ln(2)*2^{3x^2+5x-6}(6x+5)
What is the first derivative of cos(2^{3x^2+5x-6}) ?
The first derivative of cos(2^{3x^2+5x-6}) is -sin(2^{3x^2+5x-6})ln(2)*2^{3x^2+5x-6}(6x+5)