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Popular >

xy^{''}+2y^'=0

Solution

x y^{^{''}} + 2 y^{^{'}} = 0

Solution

y = c_{1} + \frac{c _{2}}{x}

Solution steps

x y^{''} (x) + 2 y^{'} (x) = 0

Solve linear ODE:

y = c_{1} + \frac{c _{2}}{x}

y = c_{1} + \frac{c _{2}}{x}

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\frac{d y}{d x} = e^{6 y} e^{6 x}

Frequently Asked Questions (FAQ)

What is the solution for xy^{''}+2y^'=0 ?
The solution for xy^{''}+2y^'=0 is y=c_{1}+(c_{2})/x