What is the integral from 1 to 18 of sqrt(3/z) ?

The integral from 1 to 18 of sqrt(3/z) is 6sqrt(6)-2sqrt(3)

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integral from 1 to 18 of sqrt(3/z)

\int_{1}^{18} \frac{3}{z} d z

66 - 23

Decimal Notation

11.23283 \dots

Solution steps

\int_{1}^{18} \frac{3}{z} d z

Apply Integration By Parts

: [\frac{3}{z} z - \int - \frac{3}{2 z ^{\frac{1}{2}}} d z]_{1}^{18}

= [\frac{3}{z} z - \int - \frac{3}{2 z ^{\frac{1}{2}}} d z]_{1}^{18}

\int - \frac{3}{2 z ^{\frac{1}{2}}} d z = - 3 z

= [\frac{3}{z} z - (- 3 z)]_{1}^{18}

Simplify

= [\frac{3}{z} z + 3 z]_{1}^{18}

Compute the boundaries:

66 - 23

= 66 - 23

- x + 7 x^{2} - 15 x

y^{^{'}} = 7 y^{2} + x y^{2}, y (0) = 1

\int \frac{x ^{2} - 6 x + 9}{x ^{2} - 6 x + 18} d x

\int \frac{1}{x ^{3} + 27} d x

x \to 0 lim (\frac{x - 4}{x - 4})

What is the integral from 1 to 18 of sqrt(3/z) ?
The integral from 1 to 18 of sqrt(3/z) is 6sqrt(6)-2sqrt(3)