What is the solution for (d^2y)/(dx^2)+16y=0 ?

The solution for (d^2y)/(dx^2)+16y=0 is y=c_{1}cos(4x)+c_{2}sin(4x)

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(d^2y)/(dx^2)+16y=0

\frac{d ^{2} y}{d x ^{2}} + 16 y = 0

y = c_{1} cos (4 x) + c_{2} sin (4 x)

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 16 y = 0

Solve linear ODE:

y = c_{1} cos (4 x) + c_{2} sin (4 x)

y = c_{1} cos (4 x) + c_{2} sin (4 x)

f (x) = - x^{3} + 2 x - e^{- x} - 3

\frac{3}{\frac{s + 2}{s}}

\frac{\partial}{\partial x} (2 x^{4} + 5 y^{2} + x y)

\int \frac{3}{x} + 10 sec^{2} (x) + 40 e^{x} d x

\frac{d}{d x} (e^{x y} cos (x + y))

What is the solution for (d^2y)/(dx^2)+16y=0 ?
The solution for (d^2y)/(dx^2)+16y=0 is y=c_{1}cos(4x)+c_{2}sin(4x)