What is (\partial)/(\partial x)(xe^{x^2+y^2}) ?

The answer to (\partial)/(\partial x)(xe^{x^2+y^2}) is e^{x^2+y^2}+2e^{x^2+y^2}x^2

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(\partial)/(\partial x)(xe^{x^2+y^2})

\frac{\partial}{\partial x} (x e^{x^{2} + y^{2}})

e^{x^{2} + y^{2}} + 2 e^{x^{2} + y^{2}} x^{2}

Solution steps

\frac{\partial}{\partial x} (x e^{x^{2} + y^{2}})

Treat

y

as a constant

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x^{2} + y^{2}}

= \frac{\partial}{\partial x} (x) e^{x^{2} + y^{2}} + \frac{\partial}{\partial x} (e^{x^{2} + y^{2}}) x

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (e^{x^{2} + y^{2}}) = e^{x^{2} + y^{2}} \cdot 2 x

= 1 \cdot e^{x^{2} + y^{2}} + e^{x^{2} + y^{2}} \cdot 2 xx

Simplify

1 \cdot e^{x^{2} + y^{2}} + e^{x^{2} + y^{2}} \cdot 2 xx : e^{x^{2} + y^{2}} + 2 e^{x^{2} + y^{2}} x^{2}

= e^{x^{2} + y^{2}} + 2 e^{x^{2} + y^{2}} x^{2}

\frac{\partial}{\partial x} (\frac{e ^{v}}{u ( v , x ) + v ^{2}})

(e^{x})^{^{'}}

f (x) = x^{5} + \frac{1}{x ^{5}}

\int \frac{2}{x ^{3}} + \frac{3}{x ^{2}} + 5 d x

x^{^{''}} + x^{^{'}} = 0

What is (\partial)/(\partial x)(xe^{x^2+y^2}) ?
The answer to (\partial)/(\partial x)(xe^{x^2+y^2}) is e^{x^2+y^2}+2e^{x^2+y^2}x^2