What is area y=sqrt(25-x^2),y=0 ?

The answer to area y=sqrt(25-x^2),y=0 is (25pi)/2

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area y=sqrt(25-x^2),y=0

area

y = 25 - x^{2}, y = 0

\frac{25 π}{2}

Decimal Notation

39.26990 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{5} - x^{2} + 25 d x

Solve

\int_{- 5}^{5} - x^{2} + 25 d x : \frac{25 π}{2}

The area is:

= \frac{25 π}{2}

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\int \frac{x ^{2} - 5}{x} d x

\frac{\partial}{\partial x} (2 y^{2})

\frac{d}{d x} (2^{\frac{1}{2}})

\int tan^{6} (x) sec^{4} (x) d x

What is area y=sqrt(25-x^2),y=0 ?
The answer to area y=sqrt(25-x^2),y=0 is (25pi)/2