What is the slope ofintercept (3,-3),(0,2) ?

The slope ofintercept (3,-3),(0,2) is y=-5/3 x+2

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slope ofintercept (3,-3),(0,2)

slope intercept

(3, - 3), (0, 2)

y = - \frac{5}{3} x + 2

Solution steps

Compute the slope

(3, - 3), (0, 2) : m = - \frac{5}{3}

Compute the

y

intercept:

b = 2

Construct the line equation

y = mx + b

where

m = - \frac{5}{3}

and

b = 2

y = - \frac{5}{3} x + 2

\int \frac{x ^{3} - 3 x ^{2} + 4 x - 9}{x ^{2} + 3} d x

- cos (2 x)

\int_{1}^{4} \frac{x - 2}{x} d x

f (x) = 3 arccsc (x)

\int x^{2} sech^{2} (x^{3}) d x

What is the slope ofintercept (3,-3),(0,2) ?
The slope ofintercept (3,-3),(0,2) is y=-5/3 x+2