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Popular >

y^{''}=xe^x

Solution

y^{^{''}} = x e^{x}

Solution

y = e^{x} x - 2 e^{x} + c_{1} x + c_{2}

Solution steps

y^{''} (x) = x e^{x}

Solve

y^{''} (x) = x e^{x} : y^{'} (x) = e^{x} x - e^{x} + c_{1}

Solve

y^{'} (x) = e^{x} x - e^{x} + c_{1} : y = e^{x} x - 2 e^{x} + c_{1} x + c_{2}

y = e^{x} x - 2 e^{x} + c_{1} x + c_{2}

Popular Examples

tangent of f(x)=x^3-2x^2+4x+3,\at x=1 tangent of

f (x) = x^{3} - 2 x^{2} + 4 x + 3, at x = 1

10x-8y*sqrt(x^2+1)(dy)/(dx)=0,y(0)=4

10 x - 8 y \cdot x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 4

derivative of f(x)=((x-5))/((x+3)^4)derivative of

f (x) = \frac{( x - 5 )}{( x + 3 ) ^{4}}

integral from 0 to 1 of-12e^x

\int_{0}^{1} - 12 e^{x} d x

derivative of x^6e^{-x}

\frac{d}{d x} (x^{6} e^{- x})

Frequently Asked Questions (FAQ)

What is the solution for y^{''}=xe^x ?
The solution for y^{''}=xe^x is y=e^xx-2e^x+c_{1}x+c_{2}