What is the limit as x approaches 0 of (4^x-10^x)/x ?

The limit as x approaches 0 of (4^x-10^x)/x is 2ln(2)-ln(10)

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limit as x approaches 0 of (4^x-10^x)/x

x \to 0 lim (\frac{4 ^{x} - 1 0 ^{x}}{x})

2 ln (2) - ln (10)

Decimal Notation

- 0.91629 \dots

Solution steps

x \to 0 lim (\frac{4 ^{x} - 1 0 ^{x}}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{ln ( 2 ) \cdot 2 ^{2 x + 1} - 1 0 ^{x} ln ( 10 )}{1})

= x \to 0 lim (\frac{ln ( 2 ) \cdot 2 ^{2 x + 1} - 1 0 ^{x} ln ( 10 )}{1})

Plug in the value

x = 0

= \frac{ln ( 2 ) \cdot 2 ^{2 \cdot 0 + 1} - 1 0 ^{0} ln ( 10 )}{1}

Simplify

\frac{ln ( 2 ) \cdot 2 ^{2 \cdot 0 + 1} - 1 0 ^{0} ln ( 10 )}{1} : 2 ln (2) - ln (10)

= 2 ln (2) - ln (10)

\frac{d}{d t} (1 + cos (t))

- 2 y^{^{'}} + \frac{4 y}{x} = \frac{y ^{3}}{x}

\frac{d}{d t} (\frac{1}{t ^{2}})

\int \frac{5 x - 1}{( 2 x + 1 ) ( x - 1 )} d x

f (x) = arctan (3 x)

What is the limit as x approaches 0 of (4^x-10^x)/x ?
The limit as x approaches 0 of (4^x-10^x)/x is 2ln(2)-ln(10)