What is the solution for (dy)/(dt)=ky(100-y) ?

The solution for (dy)/(dt)=ky(100-y) is y=(100)/(e^{-100kt+c_{1)}+1}

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(dy)/(dt)=ky(100-y)

\frac{d y}{d t} = k y (100 - y)

y = \frac{100}{e ^{- 100 k t + c_{1}} + 1}

Solution steps

\frac{d y}{d t} = k y (t) (100 - y)

Solve Bernoulli ODE:

y = \frac{100}{e ^{- 100 k t + c_{1}} + 1}

y = \frac{100}{e ^{- 100 k t + c_{1}} + 1}

\frac{d}{d x} (lo g_{4} ((x^{2} + 2 x)^{3}))

f (x) = x 8 - x^{2}

\int (1 + cos (y)) d y

\frac{π}{6} cos (x)

2 - x^{6}

What is the solution for (dy)/(dt)=ky(100-y) ?
The solution for (dy)/(dt)=ky(100-y) is y=(100)/(e^{-100kt+c_{1)}+1}