What is implicit (dy)/(dx),y=4^x ?

The answer to implicit (dy)/(dx),y=4^x is (dy)/(dx)=ln(2)*2^{2x+1}

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implicit (dy)/(dx),y=4^x

implicit derivative

\frac{d y}{d x}, y = 4^{x}

\frac{d y}{d x} = ln (2) \cdot 2^{2 x + 1}

Solution steps

y = 4^{x}

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = ln (2) \cdot 2^{2 x + 1}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = ln (2) \cdot 2^{2 x + 1}

\frac{d y}{d x} = ln (2) \cdot 2^{2 x + 1}

\frac{d}{d x} (ln (x^{2} + 14 x + 55))

\frac{4 t}{4 + t}

x \to 4 lim (x + 4)

\int - 2 x ln (x) d x

\int - 2 x^{3} d x

What is implicit (dy)/(dx),y=4^x ?
The answer to implicit (dy)/(dx),y=4^x is (dy)/(dx)=ln(2)*2^{2x+1}