What is the integral of (1-x^2)/(x+x^3) ?

The integral of (1-x^2)/(x+x^3) is ln|x|-ln|x^2+1|+C

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integral of (1-x^2)/(x+x^3)

\int \frac{1 - x ^{2}}{x + x ^{3}} d x

ln ∣ x ∣ - ln x^{2} + 1 + C

Solution steps

\int \frac{1 - x ^{2}}{x + x ^{3}} d x

Take the partial fraction of

\frac{1 - x ^{2}}{x + x ^{3}} : \frac{1}{x} - \frac{2 x}{x ^{2} + 1}

= \int \frac{1}{x} - \frac{2 x}{x ^{2} + 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x - \int \frac{2 x}{x ^{2} + 1} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int \frac{2 x}{x ^{2} + 1} d x = ln x^{2} + 1

= ln ∣ x ∣ - ln x^{2} + 1

Add a constant to the solution

= ln ∣ x ∣ - ln x^{2} + 1 + C

\frac{d}{d x} (5 x^{3} + 7 x^{2.5} - 3 x + 1)

x \to 0 lim (\frac{7 x ^{2} - 2 x}{x})

\int (\frac{4}{x} + \frac{x}{4}) d x

11 x e^{x}

\frac{\partial}{\partial y} (5 x y)

What is the integral of (1-x^2)/(x+x^3) ?
The integral of (1-x^2)/(x+x^3) is ln|x|-ln|x^2+1|+C