What is the derivative of 1+sqrt(3x) ?

The derivative of 1+sqrt(3x) is (sqrt(3))/(2sqrt(x))

What is the first derivative of 1+sqrt(3x) ?

The first derivative of 1+sqrt(3x) is (sqrt(3))/(2sqrt(x))

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\frac{d}{d x} (1 + 3 x)

\frac{3}{2 x}

Solution steps

\frac{d}{d x} (1 + 3 x)

Simplify

1 + 3 x : 1 + 3 x

= \frac{d}{d x} (1 + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (3 x)

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3 x) = \frac{3}{2 x}

= 0 + \frac{3}{2 x}

Simplify

= \frac{3}{2 x}

\frac{\partial}{\partial y} (x ln (1 + x + y))

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x \to 2 lim (\frac{2}{( x - 2 ) ^{5}})

\int \frac{( ln ( x ) ) ^{2}}{x ^{2}} d x

What is the derivative of 1+sqrt(3x) ?
The derivative of 1+sqrt(3x) is (sqrt(3))/(2sqrt(x))
What is the first derivative of 1+sqrt(3x) ?
The first derivative of 1+sqrt(3x) is (sqrt(3))/(2sqrt(x))