What is the integral of 4sin(x)-2cos(x) ?

The integral of 4sin(x)-2cos(x) is -4cos(x)-2sin(x)+C

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integral of 4sin(x)-2cos(x)

\int 4 sin (x) - 2 cos (x) d x

- 4 cos (x) - 2 sin (x) + C

Solution steps

\int 4 sin (x) - 2 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 sin (x) d x - \int 2 cos (x) d x

\int 4 sin (x) d x = - 4 cos (x)

\int 2 cos (x) d x = 2 sin (x)

= - 4 cos (x) - 2 sin (x)

Add a constant to the solution

= - 4 cos (x) - 2 sin (x) + C

\frac{d}{d x} (\frac{3 x}{x ^{2} + 2})

\frac{d}{d x} (x cos (6 x))

y = \frac{2 ( 2 x ^{5} - 9 )}{x ^{4}}

\int csc^{3} (x) sec (x) d x

\frac{d y}{d t} = y^{3}

What is the integral of 4sin(x)-2cos(x) ?
The integral of 4sin(x)-2cos(x) is -4cos(x)-2sin(x)+C