What is the derivative of y=e^{2ex} ?

The derivative of y=e^{2ex} is 2e^{2ex+1}

What is the first derivative of y=e^{2ex} ?

The first derivative of y=e^{2ex} is 2e^{2ex+1}

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derivative of

y = e^{2 e x}

2 e^{2 e x + 1}

Solution steps

\frac{d}{d x} (e^{2 e x})

Apply the chain rule:

e^{2 e x} \frac{d}{d x} (2 e x)

= e^{2 e x} \frac{d}{d x} (2 e x)

\frac{d}{d x} (2 e x) = 2 e

= e^{2 e x} \cdot 2 e

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{2 e x} e = e^{2 e x + 1}

= 2 e^{2 e x + 1}

\frac{\partial}{\partial x} (x^{3} - y^{3} + 6 x y)

\int 1 + e^{x} d x

\frac{d}{d x} (ln (x^{8} + 19))

\frac{d}{d x} (2 cos (x^{3}) - \frac{2}{x})

\frac{d}{d t} (t^{3})

What is the derivative of y=e^{2ex} ?
The derivative of y=e^{2ex} is 2e^{2ex+1}
What is the first derivative of y=e^{2ex} ?
The first derivative of y=e^{2ex} is 2e^{2ex+1}